当前位置:首页 > 开发 > 编程语言 > 编程 > 正文

Scramble String

发表于: 2015-07-08   作者:hcx2013   来源:转载   浏览:
摘要: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great":

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively.

Below is one possible representation of s1 = "great":

    great
   /    \
  gr    eat
 / \    /  \
g   r  e   at
           / \
          a   t

To scramble the string, we may choose any non-leaf node and swap its two children.

For example, if we choose the node "gr" and swap its two children, it produces a scrambled string "rgeat".

    rgeat
   /    \
  rg    eat
 / \    /  \
r   g  e   at
           / \
          a   t

We say that "rgeat" is a scrambled string of "great".

Similarly, if we continue to swap the children of nodes "eat" and "at", it produces a scrambled string "rgtae".

    rgtae
   /    \
  rg    tae
 / \    /  \
r   g  ta  e
       / \
      t   a

We say that "rgtae" is a scrambled string of "great".

Given two strings s1 and s2 of the same length, determine if s2 is a scrambled string of s1.

 

public class Solution {
    public boolean isScramble(String s1, String s2) {
        if (s1.length() != s2.length()) {
        	return false; 
        }
        if (s1.length()==1 && s2.length()==1) {
        	return s1.charAt(0) == s2.charAt(0); 
        }
        char[] arr1 = s1.toCharArray();
        char[] arr2 = s2.toCharArray();
        Arrays.sort(arr1);
        Arrays.sort(arr2);
        if (!new String(arr1).equals(new String(arr2))) {
        	return false;
        }
        if (s1.equals(s2)) {
        	return true;
        }
        for (int split = 1; split < s1.length(); split++) {
        	String s11 = s1.substring(0, split);
        	String s12 = s1.substring(split);
        	String s21 = s2.substring(0, split);
            String s22 = s2.substring(split);
            if(isScramble(s11, s21) && isScramble(s12, s22)) {
            	return true;
            }
            s21 = s2.substring(0, s2.length() - split);
            s22 = s2.substring(s2.length() - split);
            if(isScramble(s11, s22) && isScramble(s12, s21)) {
            	return true;
            }
        }
        return false;
    }
}

 

Scramble String

  • 0

    开心

    开心

  • 0

    板砖

    板砖

  • 0

    感动

    感动

  • 0

    有用

    有用

  • 0

    疑问

    疑问

  • 0

    难过

    难过

  • 0

    无聊

    无聊

  • 0

    震惊

    震惊

编辑推荐
1 String
转载http://hxraid.iteye.com/blog/522167 String对象的创建 1、关于类对象的创建,很普通的一种方
2 String
转载于Heart.X.Raid,http://hxraid.iteye.com/blog/676235 转载于Heart.X.Raid,http://hxraid.ite
3 String
转载于Heart.X.Raid,http://hxraid.iteye.com/blog/676235 转载于Heart.X.Raid,http://hxraid.ite
4 String
Java中String类由于其特殊性(不变类),几乎是笔试面试中的必考题,当然有些题目其实没啥意思,不
5 String
this关键字最大的作用就是让类中的一个方法,访问该类中的另一个方法或属性, 例如:有一个Dog类,
6 String
来源:http://www.cnblogs.com/fancydeepin/archive/2013/04/22/min-snail-speak_String.html Strin
  一:""与string.Empty我认为是一样的。网上有一篇被转载了几十遍的文章是这样说的string.Empty
C#支持两种字符串:规则字符串和逐字字符串。 我先前看到@+“”这种结构处理字符串的时候,也就只是
参考:http://www.blogjava.net/chenpengyi/archive/2006/05/04/44492.html 关于String的+操作和Str
String是不可变的字符序列,一旦被创建,就不能修改它的值.对于已经存在的String对象的修改都是重新创
版权所有 IT知识库 CopyRight © 2009-2015 IT知识库 IT610.com , All Rights Reserved. 京ICP备09083238号